The Saga of the Two Trains |

*This page is probably not what you were
expecting. *

In fact, it has nothing whatsoever to do with anything,

yet it took on such a life of its own, it could hardly be discarded.

**It began innocently enough on
October 5, 2004, when for perverse reasons of my own,
I decided to have a Newsletter with a train theme:**

**
http://www.nnhs65.com/10-05-04-NNHS-Training-Counts.html**

**Just for fun and Old Times' Sake,
I added a mathematical Train Word Problem.
Joe Madagan ('57) of FL immediately responded with another Train Word Problem. It
lay
dormant for several months, while we focused on
The Great Reunion and the
holidays
and such. Then on January 24, 2005, Joe directed our attention back to the word
problem,
and that's when the fun began.**

**LEST WE FORGET:**

**From Me ('65) of NC - 10/05/04:**

**For Old Times' Sake:**

**A Word Problem:** A freight train leaves
Chicago at 4:30 pm traveling at a speed of 60 mph. Two hours later

a passenger train leaves the same station traveling at 90 mph. How far will the
first train get before the

passenger train catches up to it?

**Translate:** D = R x T

**Answer:** The freight train
will get 360 miles away from Chicago when the passenger train catches up.

**From Joe "Adonis" Madagan
('57) of FL - 10/06/04:**

Hi, Carol:

Now you really have my attention with the Word Problem.
Here is another question: Now that the Passenger Train

caught up with the Freight Train, how long will it take the same Passenger Train to double the distance from the station

they both left?

caught up with the Freight Train, how long will it take the same Passenger Train to double the distance from the station

they both left?

If you know the answer, please do not publish it in the
same newsletter. We may have some debate that would rival the

discussions between**Ivan Goldberg ('57)** and **
Mr. Levy**,
my favorite math teacher.

discussions between

Promise you will not give the answer until we can
participate.

Always,

Joe

Joe

HA-HA!! HA-HA-HA!!!
Sweetie, I hope you don't think that I created that Word Problem myself!
There's a very good reason

that I majored in English rather than Math. It's only been in the last 15-20
years that my Word Problem nightmares have ceased.

So, don't worry, Joe. I can assure you, there's not the slightest chance that I
will spill the beans on this fun game before my return

from Illinois. ** WILD GIGGLES!!! **Thanks!

**From Joe Madagan ('57) of
FL - 01/24/05:**

Hi, Carol:

Are we ever going to see the one about the two trains
leaving the station on parallel tracks? Only Cap'n Dave knows

the correct answer. Go ahead, test the knowledge of this great group of TYPHOON.

the correct answer. Go ahead, test the knowledge of this great group of TYPHOON.

Always,

Adonis

Ah - the question of the two trains! Let's see - that was back in early October.... Ah yes, here it is:

**From** **
http://www.nnhs65.com/10-05-04-NNHS-Training-Counts.html **

**A Word Problem:** A freight train leaves
Chicago at 4:30 pm traveling at a speed of 60 mph. Two hours later

a passenger train leaves the same station traveling at 90 mph. How far will the
first train get before the

passenger train catches up to it?

**Translate:** D = R x T

**Answer:** The freight train
will get 360 miles away from Chicago when the passenger train catches up.

**From** **
http://www.nnhs65.com/10-07-04-NNHS-Kindly-Thoughts.html**

**Another Word Problem: **
Now that the Passenger Train caught up with the
Freight Train, how long will it take the

same Passenger Train to double the distance from the station they both left?

And I've still no clue..... **WILD
GIGGLES!!! **Anyone? Anyone??

**From Frank Blechman ('65)
of Northern VA - 01/26/05:**

Carol,

Everybody knows that once the passenger train gets
behind the freight train it will have to slow down

to the same speed as the freight train to avoid a collision (there are no
"passing lanes" on a railroad).

Therefore, the passenger train will never get ahead of the freight train.

The railroad riddle is like the the puzzle:

Q: If three crows are sitting on a telephone wire, and you throw a rock and
knock one off, how many

will be left on the wire?

A: (In math class) Two

A: (Anywhere else) None, because the other crows will fly away.

WHAT?!? Are you kidding me?!? Where is that problem again, lemme see............

**Another Word Problem:
**Now that the Passenger Train caught up
with the Freight Train, how long will it take the

same Passenger Train to double the distance from the station they both left?

**
Oh, for Pete's sake! YOU GUYS!! WILD GIGGLES!!!! **Thanks, Frank - and Joe!

**From Joe Madagan ('57) of
FL - 01/27/05:**

Hi, Carol:

Thank you for publishing the second edition or should I say, the continuing
saga of the **Word Problem** in your

**last** ** Newsletter**.

I hope we get a good response to this speeding train
passing the freight train, for it is very likely the **TYPHOON**

math giants who studied under__
Mr. Herman Levy__
will solve this one in a minute. At this point my one

disappointment is that__Ivan Goldberg ('57) of VA__ is
not contributing his thoughts to this Word Problem. He must

have a business email address, as he runs a real estate business in Newport News. Maybe__Nancy Bigger
Alligood __

('56) of VA could
send Ivan the link to the web page so we can get this thoughts and the answer
to this Word Problem,

if he is not too busy making the Big Bucks!!! Anyone who ever heard Ivan's exchanges with Mr. Levy would welcome a

comment from him for old times sake. They were classics. Is it really true that Ivan has mellowed with age???

math giants who studied under

disappointment is that

have a business email address, as he runs a real estate business in Newport News. Maybe

('56) of VA

if he is not too busy making the Big Bucks!!! Anyone who ever heard Ivan's exchanges with Mr. Levy would welcome a

comment from him for old times sake. They were classics. Is it really true that Ivan has mellowed with age???

Most likely the real math giants like **Cap'n Dave
(David Spriggs ['64] of VA)** will not bother to answer, shrugging it

off as too elementary. However, some of us who were a bit slow in math will take the challenge, and struggle a few

hours trying desperately to come up with the elusive answer. Of course, that is the fun of this World Problem. Keep

Training!!!

off as too elementary. However, some of us who were a bit slow in math will take the challenge, and struggle a few

hours trying desperately to come up with the elusive answer. Of course, that is the fun of this World Problem. Keep

Training!!!

Always,

Adonis

Joe, Joe, Joe. You guys are all so
adorable. I can testify to you that Frank is a Certified Genius as well. He
just took pity

on me for old times' sake.

Thanks again, Adonis!

**From** **Joe Madagan
('57) of FL - 01/27/05:**

Oh, Carol:

The __Word Problem__ is bringing me
more enjoyment than expected. After confessing that I made a keying error in
my

last contribution, where I used**World Problem** instead of
**Word Problem**, may we please proceed with seeking the

correct answer. I do not know**Frank Blechman ('65) of (Northern) VA**
well enough to run the risk of teasing him,

so I will be tactful. Frank, read the**Word Problem** again and
resubmit your answer. Please note the freight train and

the passenger train are running on__parallel__
tracks. So consider your answer, and tell us if this is your **Final
Answer?**

last contribution, where I used

correct answer. I do not know

so I will be tactful. Frank, read the

the passenger train are running on

And as for Frank's Word Problem with the three crows, I
was still contemplating my answer when upon reading further,

he gives the answer. Not fair! I was still formulating my answer.....

he gives the answer. Not fair! I was still formulating my answer.....

Always,

Adonis

Thanks, Joe! I know, I
know! I think we're just better at solving World Problems than we are at
solving Word Problems!
**
**

Okay, back to the Word Problem:

**From** **
http://www.nnhs65.com/10-05-04-NNHS-Training-Counts.html**

**A Word Problem:** A freight train leaves
Chicago at 4:30 pm traveling at a speed of 60 mph. Two hours later

a passenger train leaves the same station traveling at 90 mph. How far will the
first train get before the

passenger train catches up to it?

**Translate:** D = R x T

**Answer:** The freight train
will get 360 miles away from Chicago when the passenger train catches up.

**From** **
http://www.nnhs65.com/10-07-04-NNHS-Kindly-Thoughts.html**

**Another Word Problem: **
Now that the Passenger Train caught up with the
Freight Train, how long will it take the

same Passenger Train to double the distance from the station they both left?

Well, I still don't know.
You know, no one ever mentioned which direction these trains were headed. Where
are they going

and what will they see? How often will they brake for yard sales? Will some
bozo decide to park his car on the train tracks?

Will they be slowed by blizzards? I'm just not at all certain that we have
enough information to solve this problem. I'm *fairly *

certain that I at least shall never solve this problem! **WILD GIGGLES!!!**

**HERE COME THE TRAINS:**

**From Fred Eubank ('64) of
TX - 01/28/05:**

Carol,

I showed my 6^{th}
grader (Chris) the train ‘word’ problem and he offers the following:

The freight train (FT) will
have traveled 120 miles (60 miles/hour x 2 hours) when the passenger train (PT)
leaves the station

at 6:30. The distance formula for FT is D = 120 + 60t. The distance formula
for PT is D = 90t. When PT catches FT, the two

distances must be equal. Then, 120 + 60t = 90t. Solving for t = 4 hours, and
substituting that into either distance formula gives

D = 360 miles. Double this distance from the station is 720 miles. PT will
travel 720 miles in t = 720/90 = 8 hours. Slowpoke

FT will have traveled only 120 + (60 x 8) = 600 miles by then. Hope this
helps.

Keep up your great web work.

Fred Eubank, NNHS Class of
1964

Chris Eubank, Barbara Bush MS Class of 2007

San Antonio,
TX

Thanks, Fred - and Chris!

**From Gail Kiger Bonsey
(Ferguson HS - '73) of OR - 01/29/05:**

Freight Train
Math Word Saga continues!
**
****
**

This from **
Jim Bonsey (Kailua High - Oahu - '74)** - husband of **Gail Kiger Bonsey (FHS
'73)**:

to ever go twice the distance. At 1-1/2 times the speed, it will NEVER get twice as far" (i.e., in 1 billion hours,

the freight train will travel 60 billion miles and the

gb

Thanks, Gail - and Jim!

Then just for fun I called in my own expert:

**From my Friend, Mark
Ratledge (Reid Ross HS, Fayetteville, NC - '73; NC State - '77) of NC -
01/30/05:**

**Answer:** 4 hours. It took 4 hours to get
360 miles at 90 mph, it will take 4 more hours to get 720 miles,

double the original distance.

Thanks, Mark!

Okay, Joe - how are we doing???

**From Joe Madagan ('57) of
FL - 01/31/05:**

Hi, Carol:

which is correct.

to the lapse of time between the departure of the freight train and the passenger train. Even the example she cited

in her answer would still be the same, never. If the other three answers so far are appealed, we can arbitrate in the

court of Cap'n Dave.

Now really, wasn't that fun? Brain stimulation slows down
the aging process!

Always,

Adonis

**YEA!** I'm so glad
we have resolved the problem! And yes, it was fun! But I must confess: I'll
stick to crossword puzzles

for brain stimulation. That math section of my brain atrophied long ago! **
GIGGLES!**

Thanks, Adonis!

**From Jean Poole Burton
('64) of RI - 02/02/05:**

Carol,

I keep dreaming that we are in
algebra class and **
Mr. Taylor**
won't let us out until we solve the word problem

about the trains! Call the station. They will tell you which arrives first.

**WILD GIGGLES! **Thanks, Jean! The
trains have ceased running - and I never did find out where they were going

when they left Chicago!

**From Joe Madagan ('57) of
FL - 02/03/05:**

Hi, Carol:

Thank you and all of your faithful subscribers for
indulging me in a little fun with the word problem in the last few **
**

Newsletters.
I hope they had as much fun as I did seeing the responses, and I am so
relieved to know that **Jean **

Poole Burton ('64) of RI will cease having the recurring dream that
she could not leave __
Mr. Taylor's__
class until

the Word Problem was solved. Class Dismissed!!!

Newsletters

Poole Burton ('64) of RI

the Word Problem was solved. Class Dismissed!!!

and I was so relieved. I thought Calculus was the younger brother of Julius Caesar when I was attending

math skills sound about on par with yours, Carol.

I stole the Word Problem from a Delta Airlines inflight
magazine, so I had the full answer should a challenge come

from**Cap'n Dave (Spriggs - '64 - of VA)...**

from

And speaking of trains, we had a last minute entry from one of my local experts:

**From my friend, Rob
Powell (North Beach High School, Ocean Shores, WA - '89, United States Air
Force Academy
- '93) of NC - 02/03/05:**

As far as I can tell the answer to how long it takes to double the distance
is 4 hours. It took 4 hours for the train

to travel the 360 miles. To go another 360 would take another 4 hours. Is that too simple of thinking? Now if the

train has to slow down to follow the freight train -- it will take 6 hours to travel the same 360 miles. Not sure if this

is what you are looking for. If you want the math here it is:

to travel the 360 miles. To go another 360 would take another 4 hours. Is that too simple of thinking? Now if the

train has to slow down to follow the freight train -- it will take 6 hours to travel the same 360 miles. Not sure if this

is what you are looking for. If you want the math here it is:

(T+2)*60 = Distance traveled by
the freight train -- T+2 since it had a 2 hour head start

(T) * 90 = Distance traveled by
the passenger train

If we assume they are equal -- because the passenger train has caught up to
the freight train then the equation becomes:

(T+2)* 60 = T*90 OR 60T + 120
= 90 T

120 = 30T

T = 4

Passenger train took 4 hours to cover the distance

Freight Train took 6 hours to cover the same distance

Does this make sense?

Rob

**WOW!** Thanks,
Rob!

Rob phoned me moments
after he sent this email to tell to me that there were two ways of reading the
problem, which explains

why we had a variety of answers in an exact science. Of course, I didn't
follow exactly what he said, because my brain seems

to automatically shut off when it encounters math problems....

Sorry, **Jean** -
after Rob exerted so much effort in trying to elucidate this for us when he
was hard at work on his Master's degree

(from Webster University), I just felt it should be posted. As you'll note,
this answer is in agreement with some of the earlier ones.

Now get some sleep. **
Mr. Taylor **
will let you out of algebra class any day now.

Oh, **Jean** - pull up
a pillow and get comfy there in
**
Mr. Taylor's**
algebra class. The trains are still running..........

**From Dave Spriggs ('64) of
VA - 02/04/05:**

**Carol,
As my name has been mentioned several times in connection with the train word
problem, I can
no longer remain silent. Remember: You asked for this.
In the wonderful world of Algebra, the Laws of Physics are flagrantly
disregarded in the interest
of mathematics, e.g. velocities are achieved instantaneously. This is not the
case in the real world
of Newtonian mechanics. Both trains must accelerate from zero velocity to their
final velocity, and
this takes time. This time varies with the mass of each train and the force
applied to accelerate it ….
remember F=MA? Further complicating the issue is this: The continued of
application of force will
result in continued acceleration which will result in ever increasing velocity.
If the train engineer
wishes to reach and maintain a constant velocity, then he must reduce the force
being applied as he
nears the desired velocity. (Just think about your foot pressure on the
accelerator of your car as you
enter the interstate from the on-ramp. Push hard to get up to speed, then begin
to ease off as you reach
the speed limit.) Even worse, the force required to sustain a constant velocity
is affected by the wind
resistance to the train, and that resistance is not a constant nor is it even
linear with velocity, i.e. the
resistance at 60 MPH is more than twice the resistance at 30 MPH. So now we have
to consider the
acceleration curves from a standing start and the curves as each train
approaches its desired velocity.
All of these factors involve time, and therefore, the distance traveled by each
train as the passenger
train overtakes the freight train.
Once you lay out all the equations, you are well into differential calculus and,
perhaps partial
differential equations, as well as a host of unknown values not provided in the
original word problem.
Accordingly, my solution to the word problem is: INSUFFICIENT DATA.
**David, you're not only
adorable, you're positively delightful! Thank you so much for these elucidating
insights!

I think the important
thing to remember here is that* ***
I WAS RIGHT
- INSUFFICIENT DATA! **
WILD HYSTERICAL

GIGGLES!!!

from

**From Joe Madagan ('57) of
FL - 02/04/05:**

Dear Carol:

In your **
last newsletter** we read: "**Rob**
**(Powell - North Beach High School, Ocean Shores, WA -
'89, United States Air **

Force Academy - '93 - of NC)phoned me moments
after he sent this email to tell to me that there were two ways of reading

the problem, which explains why we had a variety of answers in an exact science."

Force Academy - '93 - of NC)

the problem, which explains why we had a variety of answers in an exact science."

Rob is right! After going back and reading the series of
__Newsletters__ pertaining to the Word
Problem, for Old Times Sake,

there are two ways of reading the problem. First, it was not clear from the beginning that the trains were running on parallel

tracks and it was not stated in the Word Problem. So those that answered that the Passenger Train would not be able

to pass the Freight Train are correct.

there are two ways of reading the problem. First, it was not clear from the beginning that the trains were running on parallel

tracks and it was not stated in the Word Problem. So those that answered that the Passenger Train would not be able

to pass the Freight Train are correct.

So, the defect lies in the vague facts in the Word Problem,
so that can make it frustrating instead of fun. Sorry I did not catch

the missing details before it was published, for I made a couple of assumptions. To**assume**, is to makes an **"**__Ass__
out of __U__

and__ME"__
(Salty Sea Language)

the missing details before it was published, for I made a couple of assumptions. To

and

Always,

Adonis

** **
Oh, Adonis - I disagree! Had this problem
been crystal clear from the beginning, we could never have had so much fun

with it! I found it almost exhilarating to realize that an exact science could
be so open to interpretation. And I never knew

word problems were *supposed* to be fun! They always frustrated the
bee-bees out of me! I thought they had a three-fold

mission: to give ulcers, raise blood pressure, and cause one to break out in
hives.**
**So thanks for the brain
teaser! It has been very educational on a number of levels!

**From Linda Lane Lane ('64)
of VA - 02/06/05:**

**As far as
the word problem regarding the train-----my Associates, Bachelors and Masters
Degrees are all in Nursing. I did learn one
helpful thing is Nursing Research. If the question doesn't answer So
What or Who Cares it probably isn't worth reading. Those
of you prone to completing the math problems will never come to a consensus.
If I can mix it and give it to you, one way or another,
then we're ok. I have decided against taking the train and am going to FLY
back to Tampa on Tuesday.
**

**From Jean Poole Burton
('64) of RI - 02/06/05:**

**NOT THOSE TRAINS AGAIN...**

Someone once told me that when God said brains,
Adam thought he said "trains" and he replied, "No, thanks, I don't

need one..." I hope all the train word problems go to the station for permanent night-night!

need one..." I hope all the train word problems go to the station for permanent night-night!

**From Carol Buckley Harty
('65) of NC - 02/07/05:**

** AWWW, Jean!
**Trains are FUN! I've only taken three train trips in my whole life, and
they were all delightful and incredibly

memorable. The first was the summer of 1949, when my parents, my sister, my
daddy's mama and his two sisters, and my

cousin **Cheryl White (John Marshall HS - '64), **all took the excursion
train from Richmond to **
Buckroe**
for a week. Aside

from the unforgettable memories, this trip added two very useful phrases to our
family's vocabulary, both courtesy of Cheryl: **
"STOP THE TRAIN!!!"**, and "No,

The second trip was in
July of 1966, when my sister, my mama, her two sisters, and my uncle took the C
& O from Richmond

to Chicago, and the Union Pacific from Chicago to Bismarck, ND for my cousin **
Clarke Booth's** **(VMI - '61) **wedding. What a

wonderful time! I had never been anywhere at all before, so it was my first
look at other parts of the country. This, too,

introduced some rich family phrases, both from my mother, delivered in her own
amazing stage whisper: "Mike! What time is it?"

and "Wake up! Wake up, everybody!! We're at Fargo! *FARGO!! * You know -
where the *STAGE COACH* runs!"

My third train trip was in
October of 2003, aboard an Amtrak train from Fayetteville to Richmond, and was
even more

enchanting than the first two.

I just LOVE trains!

**From Fred Eubank ('64) of
TX - 02/07/05:**

Carol,

Being a former engineer like
**Dave Spriggs ('64 - of VA),** I can’t let this go either.

Concerning the train problem,
Dave is absolutely right in that there was INSUFFICIENT DATA given to arrive at
a conclusive

answer, even a simple algebraic one. Here is the original problem.

**
A Word
Problem:**
A freight train leaves Chicago at 4:30 pm traveling at a speed of 60 mph. Two
hours later a passenger train leaves the same

station traveling at 90 mph. How far will the first train get before the
passenger train catches up to it?

**
Translate:**
D = R x T

**
Another
Word Problem: **
Now that the Passenger Train
caught up with the Freight Train, how long will it take the same Passenger Train

to double the distance from the station they both left?

When insufficient data is
given, the only way to arrive at an answer is to make ASSUMPTIONS. However,
what one reader

posted about “assume” is generally true.

Assumption No. 1: Are the
trains traveling on different tracks, or are they traveling on the same track?
If they are on different

tracks, then the passenger train will pass the freight train after it overtakes
it 360 miles from the station. At least one answer

was based on the assumption that both trains were traveling on the same track.
Therefore, the 90-mph passenger train would

have to slow down behind the 60-mph freight train, and not be able to pass. If
you assume they were traveling on the same

track, then that answer makes perfect sense. The problem does not say if there
were 1 or 2 tracks, so you have to make an

assumption.

Assumption No. 2: The second
part of the problem involves what happens after the passenger train overtakes
the freight train

360 miles from the station. The question is asked “…how long will it take the
same Passenger Train to __double the distance__

from the station they both left?” One has to assume “the distance” referred to
is either the distance of the passenger train

from the station, or the distance of the freight train from the station. If it
is the former, the question should have been worded

“__double its distance__”. If it is the latter, the question should have
been worded “__double the freight train’s distance__”. Now it’s

fairly obvious that if we’re talking about the passenger train doubling its
distance, the answer is 8 hours and 720 miles.

However, if we’re talking about the passenger train doubling the freight train’s
distance, then the answer is “never” since the

passenger train is traveling at 90 mph and the freight train at 60 mph. The
only way the passenger train can travel twice as far

as the freight train is if its speed is twice that of the freight train, or 120
mph. Alternatively, the freight train could slow down

to 45 mph. Again, the problem did not say which distance to use, so you have to
make an assumption.

When is Casey Jones' birthday?

**
All
Aboard!**

WILD HYSTERICAL GIGGLES!!! **
Wake up, Jean - We're at Fargo! FARGO!!**

** ** Thanks,
Fred! I think I laughed for five whole minutes!

**
http://www.infoplease.com/ce6/people/A0826558.html **

**
http://www.watervalley.net/users/caseyjones/casey.htm****
**

**
http://taco.com/roots/caseyjones.html **

**
http://taco.com/roots/caseyvillage.html **

Oh, **John Luther
("Casey") Jones** was born 14 Mar 1864 near in southeast MO, but moved to
Jordan, Fulton Co,, KY

(near Cayce - hence his nickname) when he was in his teens, and died 30 Apr 1900
near Vaughan, MS as a result of the

train wreck.

But these trains -* our*
trains - were not involved. No, they just keep going and going and going .....
**
**

**From Joe Madagan ('57) of
FL - 02/07/05:**

Hi, Carol:

**The
answer to the Word Problem furnished by ****Fred Eubank ('64) of
TX**** - published in ****
the 02/07/05 Newsletter**

was really thorough and very humorous. Assumption #2 was where we were going with this problem, and of course

he gets an A+! After reading and re-reading the earlier scholarly response of

became clear that the published

of the two trains was not disclosed earlier. Perhaps the freight train was the real

entertained during lulls in major league baseball games being called by former pitcher turned broadcaster, "Dizzy" Dean."

I sure had fun reading the responses from your vast audience of subscribers to the

I had fun too, Adonis - thanks!

**From Jean Poole Burton
('64) of RI - 02/07/05:**

All right I give up...a train story from me!

If you can't beat 'em, join 'em...:
In l979 my youngest brother was getting married in Virginia two days after we

moved into a new house. My husband could not go to Virginia with me due to work
obligations and so I decided

to take the train rather than drive with my two children, who were five years
old and fourteen months old. My

husband, who had parked in a 15 minute parking zone in Providence, got on the
train to put my suitcases on while I

had the two children in tow. He turned and his head disappeared through the
door of the car just as the train

started to move...I feared he had not gotten off the train. Sure enough, back
he comes, saying "I guess I will have

to ride to Kingston" (the next station south) In a few minutes he left to find
the conductor...back he came, saying,

"I will have to ride to New London, this train does not stop at Kingston". So
he rode to New London, caught another

train back to Providence and collected his car and parking ticket. When we got
to Newport News my parents and

my mother-in-law came to meet us at the train station.

My mother-in-law said, "I prayed all day that John would come with you".

I replied, "Well, you either prayed not enough or too much because he actually
rode with me for two hours!

** GIGGLES! **Oh, good for
you, Jean! Thanks!

**From Linda May Bond
Crayton ('66) of VA - 02/26/09:**

**From Jean Poole Burton
('64) of RI - 03/02/09 - "Oh, no, not the trains again!":**

FYI I rode the train from RI to Newport News on the 18th of February and back on the 25th. I do not know how fast it was going, how many times it stopped (a lot), or whether there were any other trains going the other way...

I do know this: I had two whole seats to myself, a lot of floor space, room to stretch my legs out, could walk two cars back and get food and drink, did not have to take off my shoes or jacket, did not have to put anything in a plastic bag, had my luggage in sight at all times, no standing in line for security...it was lovely!!!

Sounds delightful to me! Thanks, Lady!

**(This page was created on 02/08/05 for
no particularly good reason...)**

**"The Orange
Blossom Special" midi courtesy of
http://www.banjo.com,
at the suggestion of Dave Spriggs ('64) of VA - 07/04/03.
Thanks, Dave!**

**Amtrak Train
Divider Line clip art courtesy of
http://www.bravenet.com - 08/12/04**

**
Two Trains Math Problem
courtesy of
http://www.msjc.edu/math/mathcenter/handouts/Five-Step%20Strategy%20to%20Solving%20Word%20Problems.htm
- 10/04/04**

**Laughing Smiley
courtesy of Janice McCain Rose ('65) of VA - 02/07/05
Thanks, Janice! Just what I needed!**

Animated Cheering Smiley
clip art courtesy of Al Farber ('64) of GA - 08/18/05 (re-saved 02/27/09)

Thanks, Al!

NNHS65 Home Page Banner created by
my #5 Son, Nathaniel Harty (Hillsboro HS, IL - '97) of IL - 06/06/02

Thanks, Nathaniel!